f(x+3)=x^2+2x-8

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Solution for f(x+3)=x^2+2x-8 equation: 


Simplifying
f(x + 3) = x2 + 2x + -8

Reorder the terms:
f(3 + x) = x2 + 2x + -8
(3 * f + x * f) = x2 + 2x + -8
(3f + fx) = x2 + 2x + -8

Reorder the terms:
3f + fx = -8 + 2x + x2

Solving
3f + fx = -8 + 2x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
8 + 3f + fx + -2x + -1x2 = -8 + 2x + x2 + 8 + -2x + -1x2

Reorder the terms:
8 + 3f + fx + -2x + -1x2 = -8 + 8 + 2x + -2x + x2 + -1x2

Combine like terms: -8 + 8 = 0
8 + 3f + fx + -2x + -1x2 = 0 + 2x + -2x + x2 + -1x2
8 + 3f + fx + -2x + -1x2 = 2x + -2x + x2 + -1x2

Combine like terms: 2x + -2x = 0
8 + 3f + fx + -2x + -1x2 = 0 + x2 + -1x2
8 + 3f + fx + -2x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
8 + 3f + fx + -2x + -1x2 = 0

The solution to this equation could not be determined.

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